I wanted to run asterisk as user asterisk and group asterisk instead of root. I read in a post that the way to do this is to add the following two lines to /etc/init.d/asterisk:
AST_USER="asterisk"
AST_GROUP=“asterisk”
which makes sense since the script check those values and set $ASTARG accordingly, but it did not work!
After much debugging, not being that familiar with the bash shell, I discover that the line invoking safe_asterisk was not passing the parameters properly, so the following line:
daemon sh -c "$DAEMON $ASTARGS -c" >/dev/null </dev/null 2>&1 &
needs to be changed to
daemon sh -c \"$DAEMON $ASTARGS -c\" >/dev/null </dev/null 2>&1 &
else, the double quotes gets removed from the parameter list when the daemon is called, so the “-c” option of the “sh” command sees only the $DAEMON parameter, and not the $ASTARG -c .
I am surprised to see such a bug in a so important script, am I missing something???
Maybe I am not using the proper way to run asterisk as the user asterisk???
BTW, the safe_asterisk script adds the “-c” option by default unless the $CONSOLE variable is set to “no” by a script in /etc/asterisk/startup.d In other words, I do not beleive that the “-c” option should be specified in the init.d script, it could prevent someone from not setting it.
This is with Asterisk 1.8.6.0 running on CentOS 6
This was from a net install as root, and I compiled the code, it was ot a binary install.
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Some logging
“ps” without escaping the double quotes
1 S root 3765 1 0 80 0 - 1254 - 14:48 pts/0 00:00:00 /bin/sh /usr/sbin/safe_asterisk
4 S root 3767 3765 15 80 0 - 8480 - 14:48 pts/0 00:00:00 /usr/sbin/asterisk -f -vvvg -c
“ps” with the backslash to escape the double quote
1 S root 3850 1 0 80 0 - 1254 - 14:50 pts/0 00:00:00 /bin/sh /usr/sbin/safe_asterisk -U asterisk -G asterisk -c
4 S asterisk 3852 3850 20 80 0 - 8476 - 14:50 pts/0 00:00:00 /usr/sbin/asterisk -f -U asterisk -G asterisk -c -vvvg -c