I am trying to validate a user input using regex and I am not hitting the mark. I admit I am out of my element here.
I would like to make sure the user input is ether the digits 0 or 1 or is a 10 digit input that meets the [2-9]XXXXXXXXX criteria.
I have tried:
^([0-1]{1}|[0-9]{[2-9]XXXXXXXXX})$
There is an additional requirement, though not as urgent, to skip the defined enter digit timeout if the user enters the 0 or 1 since there would be no need to wait for more digits.
Can anyone guide me a little bit here? Thanks in advance!
appears to work for my urgent need, but I am still trying to figure out how to make pressing 0 or 1 instantly advance instead of waiting for the time out.
As much as I would like to say its not, this is my first regex rodeo. Can you give me an example of it in use (ideally in my use case ) to help cement my understanding.
If they push 1 or 0 it forces an early match, otherwise it has to be a 10-digit number starting between 2 and 9.
Would it be like this? ^({0!}|{1!}|[2-9]{1}[0-9]{9})$
Specifically, the Validation component of the module: Validation rule using an Asterisk regular expression (see Asterisk REGEX). For example to ensure the caller DTMF input is between 3 and 4 digits long you could use ^[0-9]\{3,4\}$ Note that the curly braces and other Asterisk special character need to be escaped.
“FreePBX is not Asterisk, they have their own support forum…”
Yes, I know, but am having no luck there and since this question is more broadly about Asterisk REGEX, I think the question still fits here. Just looking for one last little push to get me over the finish line if anyone has any expertise with Asterisk REGEX.
As I said it is Asterisk extension patterns that caters for skipping timeouts. not regular expressions. Actually, you don’t need to use patterns and ! in this case, as as there is no conflict between 0 and 1 and the pattern.